If pin 7 of the 555 is still disconnected from the rest of the circuit and the temporary wire from pin 3 of the 555 has been removed, yes.
After turning on, monitor the voltage at pin 3 of the 555, with the common lead of your multimeter (set to 20V) connected to the OV supply rail.
Th meter shoul show around 0V for around 1 second, then around 6V for one second and so on.
If wire is disconnected as I defined. the input pin to the counter should be up at 6V, so that is right.
The rest seems to be OK.
I have just rechecked the calculations and the timing should be 1 second @ 6V followed by 1 second at oV at pin 3 of the 555.
Is the 10uF capacitor definately 10uF. Is it the right way around?
Connect the meter set to 20V to the top of the capacitor with the common lead connected to 0V.
Then watch the meter for some time, the voltage should be going up and then down between 2V and 4V. See how long it takes to reach 4V and then down to 2V.
Your video shows the classic problem with the 4017. It is a ripple counter and it counts properly only when it gets clean input. Try 47pF to 470pF from pin 14 to ground, or 470K to 2.2M resistor in series to pin 14.
Your video shows the classic problem with the 4017. It is a ripple counter and it counts properly only when it gets clean input. Try 47pF to 470pF from pin 14 to ground, or 470K to 2.2M resistor in series to pin 14.
the 10 uf capacitor at the beginning of the circuit (where power and negative attach) is negative to negative + to +
the 10 uf capacitor connected to pin 6 & 2 is connected + to 6&2 negative to common ground
the 10 nf capacitor has no markings for polarity so i assumed it could go either way
both the cap at the beginning of the circuit and pin 6&2 are marked "suntang 16v 10uf"
the cap at the beginning of the circut is 0.08 and dropping
the cap at 6&2 is 0.7 and dropping
you did mean test with the red test meter lead on the top silver pad of the capacitor and the black test lead on 0v ?
edit: sorry stand by while i test again this time with the battery connected
the 10 uf capacitor at the beginning of the circuit (where power and negative attach) is negative to negative + to +
the 10 uf capacitor connected to pin 6 & 2 is connected + to 6&2 negative to common ground
the 10 nf capacitor has no markings for polarity so i assumed it could go either way
both the cap at the beginning of the circuit and pin 6&2 are marked "suntang 16v 10uf"
the cap at the beginning of the circut is 0.08 and dropping
the cap at 6&2 is 0.7 and dropping
you did mean test with the red test meter lead on the top silver pad of the capacitor and the black test lead on 0v ?
edit: sorry stand by while i test again this time with the battery connected
Is the initial cap the one across the power supply, because that always should have 6V on it.The circuit looks like it has no power: is your battery flat.
sealed lead acid 6v rechargable 1.3ah
with circuit attached it shows 6.38 bouncing to 6.36
pretty sure its still charged as its brand new only use has been doing this circuit
edit: yes the initial cap is the one at the beginning across the battery input
and with negative test lead on actual pin on (on actual chip, on top of circuit where it enters the 555)
and positive test lead on pin 8 (same way on actual chip)
i am receiving 6 v
Hmm. I'm running out of ideas.The only thing left is the 10uF cap in the 555 timming. Have you got another capacitor of even use the one on the supply input. This is a vey simple circuit which normally works no problem.