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crush said:it keeps giving me a memory alloacation error?
Nigel Goodwin said:You've posted this one! - what are you talking about?.
the gyrator acts as a constant current source. It has a time constant such that it is not fast enough to react to the incident pulse of IR (10us), hence giving me a low (square wave) signal at the photodiode.Ron H said:What is the purpose of the gyrator?
The circuit works at short distances, so i do not see how the transistor is shorting the o/p of the PD.audioguru said:Your transistor circuit is shorting the output of the photodiode.
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audioguru said:The transistor must have DC current through it for it to be a gyrator. It has only the tiny leakage current of the photodiode so it isn't doing anything.
I do have a high resisitance feedback resisitor R5, or so i thought! am i wrong? in this case i am looking to get a Vout = Iin * Rfb, which is 68000V/Aaudioguru said:The circuit should have a high resistance feedback resistor for the opamp for high gain and this resistor should bias the photodiode.
I want to implement multiples of this reciever circuit. so it has to be cost effective. ( i am also tryin to replace the AD817AN with a cheaper op-amp.. i used it cuz it was handy and it sufficed the rquirements)audioguru said:Why not use a TSOP IR receiver IC instead of re-inventing the wheel?
audioguru said:Your very low gain circuit barely works as "FAR" away as only 5cm. Is that anywhere near as good as a modern TV's remote that uses a TSOP IR receiver IC for its 10m range?