Q1a I believe you are correct
Q1 (after part a) It seems to me different ways of saying the same thing, but I would have said it the same way as you did.
Q2
I don't see any reason why you can't use DTFT for IIR systems, if it exists for the system.
I believe you are correct that stable IIR systems will have a DTFT, for causal systems. In Q1 you noted an anti-causal system where the ROC did not include the unit circle, hence the DTFT does not exist in that case.
You use the terminology "handle" which is imprecise to me. The transforms do not handle the system. They only either exist or are undefined in certain cases. When they exist, we can used them and the engineer can "handle" the system. So in your question, for a causal system the DTFT can not "handle" the unstable IIR system because it does not exist in that case. The z-transform is in better position to "handle" this case because there still may be a region of convergence outside the unit circle. But, usually if the system is unstable, we can't really handle that system in practice.
DISCLAIMER: I hope I have these correct. I find the questions not so easy because I usually deal only with causal systems, and a lot of the answers to these questions might be different than our intuition would expect in the non-causal and anti-causal cases. Since 30 years has past since I studied this formally, i could easily give an answer that is correct for the causal case but not for the other cases.
Q1 (after part a) It seems to me different ways of saying the same thing, but I would have said it the same way as you did.
Q2
I don't see any reason why you can't use DTFT for IIR systems, if it exists for the system.
I believe you are correct that stable IIR systems will have a DTFT, for causal systems. In Q1 you noted an anti-causal system where the ROC did not include the unit circle, hence the DTFT does not exist in that case.
You use the terminology "handle" which is imprecise to me. The transforms do not handle the system. They only either exist or are undefined in certain cases. When they exist, we can used them and the engineer can "handle" the system. So in your question, for a causal system the DTFT can not "handle" the unstable IIR system because it does not exist in that case. The z-transform is in better position to "handle" this case because there still may be a region of convergence outside the unit circle. But, usually if the system is unstable, we can't really handle that system in practice.
DISCLAIMER: I hope I have these correct. I find the questions not so easy because I usually deal only with causal systems, and a lot of the answers to these questions might be different than our intuition would expect in the non-causal and anti-causal cases. Since 30 years has past since I studied this formally, i could easily give an answer that is correct for the causal case but not for the other cases.