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You can't avoid the heat. It will be a minimum of 1.2A * (10V-5V) = 6W unless you go with a switching regulator.Ronv what do you think about the voltage divider? Letting the source pass through the voltage divider to have a low voltage to be fed on 7805's input. Can it help reduce the heat? Let's consider I'm operating everything at 1.2A. The starting current of the camera is 1.5A, 2A is the maximum but the cam's working current state is 1.2A.