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Using a UNI-T 139C multimeter
I now understand that breadboard causes problem but whats the point with a breadboard if not testing things before soldering?Of course it does not work. It is built on a solderless breadboard. Use a breadboard for little light bulbs or LEDs, little motors and little buzzers.
I made hundreds of my prototypes (some very complicated) with their parts and a few short jumper wires neatly soldered on stripboard. The strips of perforated copper formed half of a pcb and the parts formed the other half. They all worked perfectly and many were sold as the finished product. It was easy to see where connections were made because there was no messy tangle of wires all over the place like on your breadboard and there was no capacitive-coupling causing feedback like between your many wires ands rows of contacts. Also no intermittent contacts.
Does the oscillation affect the gain control? Because nothing is happening barely when I turn that. Just some tiny change in the shape of the soundAn inverting opamp has the input and output with opposite phases so they cancel.
A non-inverting opamp has the input and output with the same phase so just a little bit of capacitance between all the wires or rows of contacts on a breadboard causes it to oscillate.
you are ironic or is it good for real
guess it does not affect anything dont using the 1k and led?
Not ironic (sarcastic) at all, a very good meter.
The 1K resistor and LED should do no harm, but best remove them.
What is your 12V supply? can you describe in detail?
Do you have another LM358?
spec
Be better to use the desktop power supply... its a 12v computer psu. No fancy variable desktop psu.
I tested with another LM358 and the "hifi IC", with same result.
It is not a problem Rorut- you are the one doing the work and have the patience.Thanks spec! Appreciate that you have patience with me![]()
My post was not clear the resistor should have been 470 Ohms.Should I read 0v across capacitor with the mulitmeter when 47ohm is connected to the output (pin 1) and when the capacitor (100nF) is connected to 0v? (and the diode in between)
That is giving me 0.009v
Hi again Rorut,Looks like this now (whitout the resistor, diode, capacitor-thing)
still no luck with the potentiometer (gain). Tested two pots same with both.