A coil that runs on ac (alternating current) will have dc resistance. A multimeter will measure the dc resistance. When the dc resistance is measured, that won't tell you what the current and power will be when the ac supply is connected. However, the dc resistance of the contactor coil will tell you if it is a short circuit or an open circuit or a normal value. You can certainly compare it against another contactor of the same type.
I've not got a contactor here to measure, but I found an Omron relay, it's a 230 V ac MKS2PI. The coil resistance measured 4160 Ohms. That won't tell me the current that it takes, because I don't know the inductance of the coil, and the coil current is much less than a 4160 Ohm resistor would take from 240 V.
However, a look at the data sheet (
https://assets.omron.com/m/083eb9ae43a4c783/original/MK-S-Datasheet.pdf) shows me that it's close enough to the expected value, and it's not shorted or open circuit, therefore the coil circuit is almost certainly good.
If you want a 28 V supply that is capable of operating a contactor, you will need a bigger power supply than can be run from a 9 V battery. Obviously a multimeter won't operate a contactor or relay. You won't need 3 A. The contactors won't take that much current, but without knowing exactly what they are, it's not possible to know the operating current.