I don't see how.
If the MOSFET turns off for any length of time, then the output will charge to the supply voltage minus the diode drop.
How can the output go below the supply voltage?
That's what I was trying to say in my post (#8)
Can anyone pls explain how the circuit in post#4 will behave as a buck-boost.
Yes, my error. The inductor needs to have a secondary winding. I had transposed from an inverting buck/boost inverter, using a PMOSFET, without realizing the consequences.
As it stands, the circuit of post #4 is a boost controller only.
spec
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