Voltboy
New Member
Hey,
I was building a circuit, and it didn't worked for me.
When the QSE113 receive light so voltage is higher than the voltage form the pot voltage divider the output must go high. In my circuit the Output is always high, even when I put my finger over the QSE113
My question is why there is R2 because there is an open way to +V always.
I heard something of pull-up resistor, but I don't heard much, if this is the reason please tell me.
And another thing is that instead of 5v I used 3.7V (cellphone battery).
Oh.. and R1 is 10k
Thanks
I was building a circuit, and it didn't worked for me.
When the QSE113 receive light so voltage is higher than the voltage form the pot voltage divider the output must go high. In my circuit the Output is always high, even when I put my finger over the QSE113
My question is why there is R2 because there is an open way to +V always.
I heard something of pull-up resistor, but I don't heard much, if this is the reason please tell me.
And another thing is that instead of 5v I used 3.7V (cellphone battery).
Oh.. and R1 is 10k
Thanks