skyflyer54
New Member
well what do you know...I was right
the other way is pick a frequency and duty cycle target.
calculate the primary inductance from 40% of 50KHz (8uS), 20V and the "inductor ripple" of 105A*0.3 = 31.5A:
Lp = TpVp/Ip = 8*20/31.5 = 5uH
now we have three other equations to work with:
Ls = TsVs/Is, Ls = LpT^2, and Is=Ip/T
If we plug the second two into the first and solve for T we get:
T = (TsVs)/(IpLp) = (12uS*325V)/(31.5A*5uH) = 24.76 = 25:1
Hi, U mean u have 2 winding side (pri and sec side) ? The inductor i'm using is only having one winding... What type of inductor are u using?