Describe whats going on in this circuit

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Okay... Replying to the original post,

I believe that the emitter of a (NPN) transistor puts up the same voltage as that what is supplied to the base (with a small drop). Consider it as a PN Junction diode.

The current that is available at the emitter is that that is coming from the collector as the base current is very small - few microAmpers.

The zener and the resistor forms a potential divider to give a constant stable voltage to the transistor base irrespective of the change in input voltage..
 
Either this is some strange kind of breadboard, or it's not hooked up right.

I see:
Red, Yellow, E, and C are connected together.
Base isn't connected to anything.
1.2K resistor isn't connected to anything.
Diode cathode is connected to Black.
Diode anode isn't connected to anything.

Summary: output equals input. Circuit has no effect.

Needs to be rewired after an understanding of the breadboard's interconnect is gained.
 
YUP YOU ARE RIGHT i was doing this too late at night, thanks for pointing it out. Ill revised it
 
yes i conected most of it wrong, sorry should have revised it before. Where can i find the specs for my 2n3904 transistor? I'll google it see what i can find
 
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