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Its a 5V source & it doesn't have any high voltages.Specially this diode was in a app note a low power clock.UNderstand?
High voltage does not need to be high. For 3.3V circuit, 5V from voltage spike or ESD shock can be too high. ESD shock especially much much higher (1000s of volts).
But yeah, specified LED is normal and not used for this purpose. I don't know what it does. Maybe reverse polarity protection? Usually diode like this would burn out in that case, but may save circuit if problem was realized and circuit disconnected right away. Reverse polarity protection diode in series works better and protects for longer, but has voltage drop on output. Parallel diode doesn't protect for very long but has no voltage drop on output.
So Finally that diode is for reverse voltage protection without a voltage drop.
Here after is it ok if I add diodes in parallel instead of series to Vdd.
hi Suraj,
The diode/s you are posting about are not in 'reverse parallel' connection, thats a different configuration.
Reverse parallel is where two diodes are connected in parallel with each other,
the anode on one diode being connected to the cathode of the other.
So they form an 'ac' type clamp, which 'clamps the 'ac' signal to about +/- 0.7V.
The diode you have posted is a reverse voltage protection diode and as already been pointed out you should have a series fuse in the supply line.
Hi ericgibbs thanks for correcting that mistake.
Oh I see its a reverse voltage protection diode.Can I use it without a fuse If I supply 5V.