Continue to Site

Welcome to our site!

Electro Tech is an online community (with over 170,000 members) who enjoy talking about and building electronic circuits, projects and gadgets. To participate you need to register. Registration is free. Click here to register now.

  • Welcome to our site! Electro Tech is an online community (with over 170,000 members) who enjoy talking about and building electronic circuits, projects and gadgets. To participate you need to register. Registration is free. Click here to register now.

Help calculate VTH

Status
Not open for further replies.
Apply Thevenin's method.. You've been taught this already.
 
I do not understand the method of Thevenin, have difficulties in calculating the VTH with a current source circuit ...

help me
 
What difficulties are you having? Please express the EXACT trouble that you're having, and YOUR methods for having come up with them.
 
The first three lectures of this series will help you understand a number of methods to answer any questions:

https://ocw.mit.edu/courses/electri...e/6-002-circuits-and-electronics-spring-2007/

I'm unsure what you mean by "VTH" in relation to the circuit pictured. However you can simplify the circuit to help you, have a think about how many resistors there really need to be. That will make any maths much easier.
 
NOBODY get??

Some of us do.

Basically you are replacing voltage sources with shorts, and current sources with opens.

Start by opening (removing) the current source. The circuit decomposes into 2 simple resistive divider loops, one at the top of the voltage source, one at the bottom. Calculate the voltage drops around the circuits per Kirchoff and Ohm. Write them down.

Next, replace that voltage source with a short circuit. Now calculate the equivalent resistance as seen from the current source, make it a 2-resistor divider so the voltage source will be in the middle. Now calculate the voltage drops on that (hint: the top one will be 12V). No go back and add these drops algebraically to the voltages given in the previous step. The two resistors on the right (top and bottom) are in series, so they will have to be treated as dividers and re-calculated. If you have done this correctly, the three voltage drops of the resistors around the top and bottom of the 115V source will add to 115V.

Strictly speaking, you need a pair of output nodes to calculate the Thevenin voltage and resistance equivalents. You have not specified those.
 
Last edited:
Status
Not open for further replies.

Latest threads

New Articles From Microcontroller Tips

Back
Top