OK, Here is a bit on how it works:
R4, R3, and U4 form a voltage divider from +12 and ground. The wiper on the potentiometer (U4) can be set to .65 volts. This signal is applied to the positive terminal of the op amp making it's output go positive. This turns on the FET. The FET turns on until the voltage drop across the .13 ohm resistor also = .65 volts. This represents a current of 5 amps (.65 volts/.13 ohms = 5 amps. The circuit is what is called closed loop so the current will remain at 5 amps even if the +24 drops.
U5 is just an amplifier with a gain of 7.66 times. It amplifies the voltage across the .13 ohm resistor. So .65 volts X 7.66 = 4.98 volts (call it 5). This displays 5 volts on the meter that = 5 amps per FET or 50 amps.
Same deal with U6 except the gain is 10X. The output of the temperature sensor is 0.01 volts per degree C or 1 volt per 100 C. So at 88C the output will be 8.8 volts to the meter.
U1 is a comparator. The output of the comparator will go to ground if the temperature sensor goes above .88 volts (88C). If this happens the output will ground the bottom of R4 making the + side of the op amp go to ground thus "asking" for 0 volts (no current) across the .13 ohm resistor. It will also sound the alarm and light the LED.
Because U1 has positive feedback the temperature must go belo 76C before things will start over.
We can make it go higher - how about 60 amps? This will be pushing the temperature limits when running the 24 volt supply but you will probably have more water than () had in his test.
Hope this helps.
R4, R3, and U4 form a voltage divider from +12 and ground. The wiper on the potentiometer (U4) can be set to .65 volts. This signal is applied to the positive terminal of the op amp making it's output go positive. This turns on the FET. The FET turns on until the voltage drop across the .13 ohm resistor also = .65 volts. This represents a current of 5 amps (.65 volts/.13 ohms = 5 amps. The circuit is what is called closed loop so the current will remain at 5 amps even if the +24 drops.
U5 is just an amplifier with a gain of 7.66 times. It amplifies the voltage across the .13 ohm resistor. So .65 volts X 7.66 = 4.98 volts (call it 5). This displays 5 volts on the meter that = 5 amps per FET or 50 amps.
Same deal with U6 except the gain is 10X. The output of the temperature sensor is 0.01 volts per degree C or 1 volt per 100 C. So at 88C the output will be 8.8 volts to the meter.
U1 is a comparator. The output of the comparator will go to ground if the temperature sensor goes above .88 volts (88C). If this happens the output will ground the bottom of R4 making the + side of the op amp go to ground thus "asking" for 0 volts (no current) across the .13 ohm resistor. It will also sound the alarm and light the LED.
Because U1 has positive feedback the temperature must go belo 76C before things will start over.
We can make it go higher - how about 60 amps? This will be pushing the temperature limits when running the 24 volt supply but you will probably have more water than () had in his test.
Hope this helps.