The numbers from a data sheet do not mean the FET will all wise work like that.
In your example from the first post: 10 volts is applies from G-S. A current source (2.7A) is applies to the D. The FET looks like a 1.35 ohm resistor. The voltage D-S is 3.6 volts, under these conditions.
Appling 10 volts to the gate will not cause 2.7 amps. It will cause the FET to turn on and look much like a 1.35 volt resistor. The current is a function of what is on the D.
Early Effect Voltage???? Are you talking about the first nano-seconds of turn on? Saturation is talking about being on (DC) not AC.
This is a common misconception for people who cut their teeth on BJTs. Saturation in a MOSFET is basically opposite of that in a BJT. In a MOSFET, saturation is the high-impedance region (active mode) of the characteristic curves.
I know the early effect voltage (VA) is normally applied with BJT's. I don't know if it is applicable with FET's. It is actually the variation of the width of the base as the reverse voltage between collector base varies. Typically, the gate of the FET's as virtually isolated, high impedance input.
I know the early effect voltage (VA) is normally applied with BJT's. I don't know if it is applicable with FET's. It is actually the variation of the width of the base as the reverse voltage between collector base varies. Typically, the gate of the FET's as virtually isolated, high impedance input.
similar to the way the VA describes the linear dependency of IC on VCE in saturation region in BJT, it also describes the linear dependency of IDS on VDS in saturation region in MOSFET.