The input capacitance of the MOSFET is 2000uF.
That can't be right.
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The input capacitance of the MOSFET is 2000uF.
none of which effects the reflected voltage or the fact that leakage inductance exists.You know as well as I that coupled inductors (a.k.a. flyback transformers) and transformers have completely different design procedures. Without knowing the cores inductance factor, cross section, material... etc. and at what point the unit is to enter CCM, how did you cone up with those numbers?
...in the mean time let me dig up a few links.
none of which effects the reflected voltage or the fact that leakage inductance exists.
The duty cycle at which a flyback converter is running at has NOTHNG TO DO WITH WHAT THE PLATEAU VOLTAGE ON THE PRIMARY MOSFET DRAIN WILL BE!!!!
How may references would you like to see before your convinced that it's Vout reflected thru the coupled inductors turns ratio + Vin???
Lloyd Dixon wrote a lot of good stuff on magnetics while at Unitrode/TI... read some of his thoughts on flybacks... in the mean time let me dig up a few links.
Because I've been designing DC-DC for the past 19 years of my 35+ year career at the worlds #1 DC-DC prodcucer and the #4 AC-DC producer, that's why DUDE!
When measuring resistance between gate and drain we dont get any results. Seems like it is infinite resistance. Not sure what you mean about "funny" results here. Could you explain that?
But Vout is determined by the duty factor. The FET turns on and energy builds up. The FET is switched off. The secondary winding discharges into the diode & output. The Vout value is simply Vin*(D/(1-D) times the turns ratio. In other words Vout is determined by Vin, the turns ratio, & the duty factor. To get high values of Vout, a large duty factor is needed, or turns ratio. SO it definitely matters as to duty factor.
Not just the spike. Also the waveform that comes out from the PWM when applying voltage at the input. The square signal looks more like a sinus. Its those two problems that we are not able to solve :/
You have no idea how grateful we are that you are willing to help us out!
it takes 8mA 440nS to discharge the 2.2nF osc cap 1.6V... reduce it to 500pF with a 4K resistor. the data sheet says it will be 30% dead time...