trying to understand
rather then just building it, I’m trying to understand how people have calculated the values for various components for the stun gun picture attached.
Looking at this person website for some help (and also using my brain):
http://www.kpsec.freeuk.com/trancirc.htm
To calculate the base resistance for the transistor (tip 31) you need voltage and current:
First, using basic ohms law.
- The difference between the emitter and base should be about 0.6 V
i know the output voltage from the 555 timer is about 1.7 v less then Vcc. so if you have 9 volt supply then 7.3 Volt would on pin 3.
so therefore the voltage difference across the base resistance would be 7.3-0.6 = 6.7 Volts. ok
Now for the current.
(Using the above website and the attached datasheet for tip31)
The load current is 9 volts/8 ohms =1.125 amps
Using the datasheet attached, looking at the graph of Ic vs Hfe, 1000 mA, hfe is about 100.
Therefore Ib current is about 1.125/100=0.01125 amps.
Therefore the resistance would be about 6.7/0.01125=600 ohms
if you use the method as described by the website, you would get about 130 ohms.
i can see 600ohms is close to 1000ohms, but if you used 1000 ohms, would you not get about 0.67 amps passing through the transformer. Or is my understanding flawed.
At the moment I am having difficulty trying to get this circuit to work. I can get the 555 timer to work, but when it comes to getting a voltage across the transformer I get nothing.
I can get current flowing through the base of the transistor, but it is a lot lower then I have calculated even with a fresh battery.
Can someone correct me if I’m wrong about the above.