OK.
I think this will do what you want.
It is the mostly the same as the last circuit but with a few modifications.
See circuit below for the following comments.
1. I've replaced the input signal differentiator circuit with a "dual edge detector" circuit. The dual edge detector generates a pulse when the input changes voltages levels. It doesn't matter whether level changes from high-to-low or low-to-high. It will produce a pulse on either change.
2. I've reconfigured the reset (pin 10) of the Toggle flip flop with a "Power On Reset (POR)". This ensures the Toggle flip flop "Q" is set low at power up.
3. I've re-wired the 555 timer so that the output drives the relay via the TBD62003A. When the door is opened the timer is enabled so its output immediately goes high, begins the timing, and energizes the relay. If the timer expires, the relay will de-energize. If the door is closed before timeout, the relay will also de-energize. If the door is opened again, the sequence starts over.
4. I changed the wiring of the Blue LED to reflect the status of the door. Basically, anytime "Q" of the toggle flip flop is high, the door is open.
I thought it would be more useful that way since now the timer LED reflects the state of the relay. We can change it if you prefer.
5. One thing that is a mandatory requirement for this circuit to work is that the Micro-switch or Touch module must "latch" its output.
This is easy for the Micro-Switch, but the Touch-Switch must latch its output on touch detection. I think the one you have will do that.
It doesn't matter, however, whether the output initially low and changes to high, or visa-versa, as long as it hold its state (no pulsed output).
You shouldn't need any more parts. The changes I made use existing parts.
I have the modified circuit on the breadboard and its working as intended.
Let me know what you think.