Hi,
Yes, this is my college work, but i have attempted it and need a just need a few things clarified for me....
Using a 48kVA, 4800/240 V step down transformer:
open circuit test: V = 240V, I =2A, P = 120W
short circuit test: V= 150V, I=10A, P =600W
O.k in o/c i get:
Rc = (V^2) / W = (240^2) / 120 = 480 ohm
Xm = 124 ohm
and in s/c i get:
R= W / (I^2) = 600 / (10 ^2) = 6 ohm
Xl = 13.7 ohm
Do these values seem correct?
I have to determine the equivalent circuit viewed from the high voltage side, is my attempt (see attached) correct?
To find the rated current in the primary is this just 48kVA / 4800 = 10A?
I appreciate this site is not for students to get their homework done for them, but if someone could look over what i have done that would be most appreciated....
Thanks in advance
elec123
Yes, this is my college work, but i have attempted it and need a just need a few things clarified for me....
Using a 48kVA, 4800/240 V step down transformer:
open circuit test: V = 240V, I =2A, P = 120W
short circuit test: V= 150V, I=10A, P =600W
O.k in o/c i get:
Rc = (V^2) / W = (240^2) / 120 = 480 ohm
Xm = 124 ohm
and in s/c i get:
R= W / (I^2) = 600 / (10 ^2) = 6 ohm
Xl = 13.7 ohm
Do these values seem correct?
I have to determine the equivalent circuit viewed from the high voltage side, is my attempt (see attached) correct?
To find the rated current in the primary is this just 48kVA / 4800 = 10A?
I appreciate this site is not for students to get their homework done for them, but if someone could look over what i have done that would be most appreciated....
Thanks in advance
elec123