Continue to Site

Welcome to our site!

Electro Tech is an online community (with over 170,000 members) who enjoy talking about and building electronic circuits, projects and gadgets. To participate you need to register. Registration is free. Click here to register now.

  • Welcome to our site! Electro Tech is an online community (with over 170,000 members) who enjoy talking about and building electronic circuits, projects and gadgets. To participate you need to register. Registration is free. Click here to register now.

555 driving N mosfet

Status
Not open for further replies.

MrDEB

Well-Known Member
Working on a method to have an adjustable flash on an LED neon strip.
Have attached the schematic for the test circuit, plan to use a 7805 to power the 555 but testing with a 9v battery I get 4 volts on the 555 output.
The issue is the gate has a maximum of 4v on the gate.
thinking of a voltage divider or Zener diode on the gate to avoid applying too much voltage to the gate.
I show 2 LEDs but D3 is just for testing. D2 will be a 12v LED neon strip. the 9v will be 12 v.
and yes the breadboard circuit works as showen
 

Attachments

  • 555 and mosfet.png
    555 and mosfet.png
    34.1 KB · Views: 392
You need to link datasheets, part numbers and why no heatsink? That schematic is not helpful.
To switch 2A and only dissipate 0.2 W (not too hot) you need a 0.1V drop (2A*0.1V=0.2W) which means Ron = 1V/2A = 0.5 ohm

The IRF520 is 0.27 ohm max at Vgs=10 but more than 2x this at 150'C so a heatsink is needed.

Use 12V for gate voltage.
 
Here's an update to follow if you like the 30:1 frequency range You can make the IRF520 work if you follow my advice. Use 12V for gate voltage add small heatsink. There are about 1,000 logic level FETs to choose from.

 
Last edited:
The Vgs(th) is the gate voltage that turns it OFF, you need the gate voltage that turns it ON which is usually 10V for a common old Mosfet. A moderm "logic level" Mosfet fully turns on with a 5V gate voltage.
 
Technically Vt or Vgs(th) or gate threshold voltage is defined by the range of voltages due to mfg tolerances that result in current of 250µA with Vgs=Vds. So iif Vt was say 2.5V then RdsOn= 2.5V/0.25 mA = 10 kohm. . not quite off or on.
 
Last edited:
I can't remember how many Amps his LED strips will draw, way more than 0.25mA.
Yes we know very dim in the dark, probably off, but not recommended to prevent acceleration of matalization and LM70 wear times.
 
the Vgs(th) states 1-2v
1. OK with 1 to 2V actually with 12V gate drive you can use 2 to 4V too. ok?
2. I gave 0.2 ohm as a limit for the example using the IRF FET getting hot (TO220 without a heatsink and not an ideal target for a FET resistance. ok?

3. But there are tons of different FETs in catalogs, so why not get one to handle 5A easily. or RdsOn of <= 25 mohms. 5^2 * 0.025 = 63 mW , cool ')

I suggest for you, https://www.mouser.com/ProductDetail/onsemi-Fairchild/NDP6060?qs=7qg/USZkK87eR6XCHfQYeA== in future.
 
Status
Not open for further replies.

Latest threads

New Articles From Microcontroller Tips

Back
Top