No, while the DC current gain is important, a wide range of current gains will be suitable for your power supply. The 2N2905 is an excellent transistor, but unfortunately it is obsolete now.
but I think that Q1 should act as an amplifier and that it should operate in the amplification part of its curve, not the switching part? Or am I confusing things?
Yes, both transistors will work fine, but note my previous comment, that you will need a more powerful transistor on a heatsink when you start taking any significant current from the PSU.
No probs. There is a chance that there is an internal connection to pin 8. If that is the case connecting pin 8 to 0V may be upsetting the LM723. Unfortunately, there is also a chance that the LM723 will be blown.
Hi spec,
If the recents posts are referring to the schematic in post #76 then I think there is an error in it. Pin 10 (VO) (The emitter of the internal pass transistor.) should be connected to a more negative point so the collector of the internal pass transistor (pin 11) can pull the base of Q1 negative to turn it on.
Hi spec,
If the recents posts are referring to the schematic in post #76 then I think there is an error in it. Pin 10 (VO) (The emitter of the internal pass transistor.) should be connected to a more negative point so the collector of the internal pass transistor (pin 11) can pull the base of Q1 negative to turn it on.
Thanks for the observation about the circuit of post #76.
Above is the LM723 functional diagram from post #9. A 56K resistor connects between 39V and pin 10 of the LM723 to bias the 6.2v Zener in the LM723 on. Vz (pin 9) is then connected to 0V. This is done because the base of the series pass transistor in the LM723 will not operate at 0.6V above 0V.
The collector of the series pass transistor is then connected to the base of the PNP output transistor driver.
You are right Les. I am not sure how I managed it, but I was looking at the schematic of post #69 instead of the schematic of post #76. Anyway, I have rebooted and cleared the cache on my laptop and can now see the correct schematic that you refer to.
You are right Les. I am not sure how I managed it, but I was looking at the schematic of post #69 instead of the schematic of post #76. Anyway, I have rebooted and cleared the cache on my laptop and can now see the correct schematic that you refer to.
earckens, you need to connect Vz (pin 9) to 0V, as Les says.
Hi spec and Les, I am sorry for the confusion caused between posts 69 and 76. Currently it is the schematic of post 76 which is used in the prototype, and which also was in use in my first PSU made 30 years ago.
But ok, I will 1. disconnect pin 8 and 2. connect pin 9 (Vzener) and 3. buy a new LM723 for the prototype
This afternoon this will be executed and reported back to you.
Hi spec and Les, I am sorry for the confusion caused between posts 69 and 76. Currently it is the schematic of post 76 which is used in the prototype, and which also was in use in my first PSU made 30 years ago.
But ok, I will 1. disconnect pin 8 and 2. connect pin 9 (Vzener) and 3. buy a new LM723 for the prototype
This afternoon this will be executed and reported back to you.
The voltage across the current sense resistor (0.12 ohm 5W)is not being used. I think the bottom of the current limit pot should go to the input end of that resistor.
Eric, Can you repeat the test with the current limit pot set to the 0 volts end of the track. I think the current limit may be comming into play to drop the output voltage.
Hi Les, I think you hit a major snag! I just checked my initial notes from when I reverse engineered the original pcb and I notice that I did overlook the different ground potentials to be used!
From my notes I think to deduce that following items should be connected to the "input" of the 0.12 ohm resistor:
CS (pin 3)
the 2.2nF capacitor on the CS side
I am not able to deduce whether the grounds for the current sense pot have to be connected before or after the 0.12 ohm resistor; same for voltage pot ground (although I think to remember they were connected at the output of this resistor).
Now what I will do, based on your comment, is to first connect CS and 2.2nF to the input of 0.12ohm. Subsequently also connect the pot grounds there.
I will report back tomorrow (my missus wants to spend evening time together )