“When C1 discharges from 5.6v to 3v through C2 it releases stored energy, and delivers current into point A. “
Because you have never drawn the high-speed diode “flipped-over” you don’t understand that point A is actually at a potential of -0.6v during this part of the cycle.
”there is a RC time delay formed by RZ and C1”
How long do you think it will take to charge C1 via a 10k and provide enough energy to turn on the transistor????? (as well as the leakage into the zener.)
The electo on the output does this via the inductor and 1n.
You have a completely wrong idea of how the circuit works.
Because you have never drawn the high-speed diode “flipped-over” you don’t understand that point A is actually at a potential of -0.6v during this part of the cycle.
”there is a RC time delay formed by RZ and C1”
How long do you think it will take to charge C1 via a 10k and provide enough energy to turn on the transistor????? (as well as the leakage into the zener.)
The electo on the output does this via the inductor and 1n.
You have a completely wrong idea of how the circuit works.