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Why do you want to overload the output of the opamp with your VERY low resistor values of 200 plus 10 ohms?
Those resistors connect from the output of the opamp to ground (creating negative feedback) so then they are a load of 210 ohms. The datasheet of the OPA2134 and for every other opamp shows that when the load is 10k ohms or higher then the performance is fairly good. But is shows that when the load is 2k ohms or less then the performance (distortion) is awful and the opamp overheats.
You do not understand the importance of the capacitor in series with the feedback resistor to ground so I give up explaining the basics of electronics to you!
A buck converter efficiently reduces the voltage by oscillating which creates noise. A linear voltage regulator like a 7805 reduces the voltage but wastes power by making heat but it produces no noise. The datasheet for the 7805 shows an important input capacitor and an important output capacitor. Depending on how much current the DVR uses a lower power 78M05 or a small 78L05 can be used.
Good to know. I did more testing (suggested by jjw on allaboutcircuits) and regardless of whether I use 9v or 12v, I get the noise. However, the noise goes away as soon as I disconnect the pos/neg leads from the DVR. I tested this with and without the aud-in/out connected also. Same result. If I have the DVR supplied with the same power as the circuit, I have noise. The audio is perfect without the DVR connected, or DVR supplied by separate battery source. I think that I would rather use a separate source for the DVR (9v batt) than have to create additional circuitry and burn 5.6W of juice while needing a heat sink also.... do you agree?A 7805 is in a case with a metal tab. The metal tab can be screwed to a heatsink to cool the device. The heat is caused by the voltage from its input to its output times the current in it so if the input is 12V and the current is 800mA then its heating is (12V - 5V) x 800mA= 5.6W. If it is in 25 degrees C air and is not enclosed then it will overheat and fail if it dissipates more than 2W without a heatsink. It is rated at 1A but most can produce 1.5A.
I question the 800ma, but your point is well taken. That would not work. So how would I go about setting up a filtered supply to the mic? Can that filtered supply come from the same 12v battery that is supplying everything now? Job for a capacitor?You said the DVR current might be 800mA. But an ordinary 9V alkaline battery is dead in 1 hour at only 250mA and might not produce 800mA for only a few seconds. Six AA alkaline cells produce 9V but at 800mA they are dead in about 1.5 hours.
Maybe your noise is caused by feedback from the power supply into the mic preamp. The resistor that feeds the microphone must be fed from a filtered voltage, not directly from the power supply that might have its voltage bouncing up and down a little with noise or the signal.
With an input of 12.0V then the 2N3055 transistor and the 12V zener diode do almost nothing. They produce an output of 11.3V when the output current is only 160mA, the input is 13.2V and the 2N3055 has low current gain. The 5V regulator works well with the original 12V as its input. Why do you need 12V to be regulated?
The LM309k and 2n3055 are in huge steel old fashioned packages.
Your last schematic showed the microphone powered with a 22k resistor from 12VDC. But the microphone's current is about 0.5mA and might be a little more at 0.6mA. Then its power supply must be higher than (0.6mA x 22k) +1.5V= 14.7V so the 22k resistor value is much too high.
A 4.7k resistor from +12V with 0.5mA in it produces 9.65V and a 10k resistor feeding the mic will produce 4.65V across the mic so it does not produce distortion when sounds are loud. The 9.65V junction of the two resistors will be 9.18V when the mic current is a little high at 0.6mA which is fine. The junction of the two resistors can be filtered with a 100uF capacitor to ground. But if the DVR is powered from the 5V regulator then the mic can also be powered from the 5V regulator through a 5.1k or 4.7k resistor.
An electret mic is not an LED. An LED sets its own voltage but the resistor value, the supply voltage and the current draw of an electret mic sets its voltage that your calculator did not calculate.I used an online resistor calculator
The mic will work but the noise might not be gone.I like the idea of powering the mic with the 5v. So, I would have the DVR & mic on a regulated 5v supply (4.7k resistor before mic) and the opamp on the 12v battery supply.... Maybe that would also solve my noise issue and eliminate the need for a separate 9v battery?